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PhysicsCurrent ElectricityElectrical instrumentEasy2 minPYQ_2022
PhysicsEasysingle choice

Two identical cells each of emf1.5 Vare connected in parallel across a parallel combination of two resistors each of resistance20 Ω. A voltmeter connected in the circuit measures1.2 V. The internal resistance of each cell is :

Question diagram: Two identical cells each of emf 1 . 5 V are connected in par

Options:

Answer:
C
Solution:

Equivalent resistance of the parallel 20 Ω branches will be 10 Ω.

Equivalent EMF of the two branches which are in parallel will be, =1.5r+1.5r1r+1r=1.5 V and the equivalent internal resistance for same branches will be, r2.

For loop containing voltmeter and 10 Ω resistor, 1.2-10i=0 i=0.12 A.

Reading of voltmeter should be,

1.2=1.5-ir2 ir2=0.3 r=0.6i=0.60.12= 5 Ω

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical instrument
2mℹ️ Source: PYQ_2022

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