A wire of length ' 1 and resistance 100Ω is divided into 10 equal parts. The first 5 parts are connected in series while the next 5 parts are connected in parallel. The two combinations are again

Question

A wire of length ' 1 and resistance 100Ω is divided into 10 equal parts. The first 5 parts are connected in series while the next 5 parts are connected in parallel. The two combinations are again connected in series. The resistance of this final combination is:NEET 2024

TestHub · Accepted Answer

Divided into 10 parts R R ′ R S ​ R S ​ R P ​ R eq ​ ​ = A ρl ​ = 10 A ρl ​ = 10 R ​ = 5 × 10 R ​ [series] = 50 = 50 R ​ [parallel] = R S ​ + R P ​ = 52Ω ​

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