A gas mixture consists of 2 moles of oxygen and 4 moles of neon at temperature T . Neglecting all vibrational modes, the total internal energy of the system will be:

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TestHub · Accepted Answer

The internal energy of a gas is given by $U = n C_{V} T$ .
A diatomic gas has $3$ translational and $2$ rotational degrees of freedom. A monoatomic gas has $3$ translational degrees of freedom.
Hence, the internal energy of the mixture $= n_{1} C_{V_{1}} T + n_{2} C_{V_{2}} T$
$= 2 \times (\frac{5 R}{2}) T + 4 \times \frac{3 R}{2} T = 5 R T + 6 R T$
$= 11 R T$

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