Physics - Current Electricity Question with Solution | TestHub

The net electromotive force in the loop is the difference between the two opposing batteries.

$E_{\text{net}}=15-5=10\text{V}$

The total resistance in the loop is $R=25\Omega$.

Using Ohm's law, the current $I$ is given by:

$I=\frac{E_{\text{net}}}{R}=\frac{10}{25}=0.4\text{A}$

Answer: $0.4\text{A}$