Ratio of thermal energy released in two resistor R and 3 R connected in parallel in an electric circuit is :

Question

TestHub · Accepted Answer

In parallel connection, potential difference across resistors remains the same.

Thermal energy released in resistor is given by $H = \frac{V^{2}}{R} \times t$

So, the ratio is $\frac{H_{1}}{H_{2}} = \frac{\frac{V^{2} t}{R}}{\frac{V^{2} t}{3 R}} = \frac{3 R}{R} = 3 : 1$ .

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