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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityMicroscopicMedium2 minPYQ_2009

PhysicsMediumsingle choice

The mean free path of electrons in a metal is $4 \times 1 0^{- 8} m$ . The electric field which can give on an average $2 eV$ energy to an electron in the metal will be in unit of $Vm^{- 1}$ NEET 2009 (Screening)

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Answer:

Solution:

$Energy eV_{0} \Rightarrow V_{0} = 2 eV = 2 eV = 2$ Now, electric field $E = \frac{2}{4 \times 1 0 ^{- 8}} = 0.5 \times 1 0^{8} = 5 \times 1 0^{7} Vm^{- 1}$

Stream:NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Microscopic

⏱ 2mℹ️ Source: PYQ_2009

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