Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical PowerMedium2 minPYQ_2022

PhysicsMediumsingle choice

Power dissipated across the $8Ω$ resistor in the circuit shown here is 2 watt. The power dissipated in watt units across the $3Ω$ resistor is

Options:

Answer:

Solution:

Power $= V . I = I^{2} R$ $i_{2} = \frac{Power}{R} = \frac{2}{8} = \frac{1}{4} = \frac{1}{2}$ Potential over $8Ω = Ri_{2} = 8 \times \frac{1}{2} = 4 V$ This is the potential over parallel branch. So, $i_{1} = \frac{4}{4} = 1$ Power of $3Ω = i_{1}^{2} R = 1 \times 1 \times 3 = 3 W$

Stream:VITEEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

⏱ 2mℹ️ Source: PYQ_2022

Doubts & Discussion

Loading discussions...