A current of 10 A exists in a wire of cross-sectional area of 5 mm 2 with a drift velocity of 2 × 10 - 3 m s - 1 . The number of free electrons in each cubic meter of the wire is

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i = 10 A , A = 5 mm 2 = 5 × 10 - 6 m 2 and v d = 2 × 10 - 3 m s - 1 We know, i = n e A v d ∴ 10 = n × 1 . 6 × 10 - 19 × 5 × 10 - 6 × 2 × 10 - 3 ⇒ n = 0 . 625 × 10 28 = 625 × 10 25

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