Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical PowerEasy2 minPYQ_2020

PhysicsEasysingle choice

In the arrangement of $3$ bulbs of $100 W$ each as shown in the figure, total power consumption will be

Options:

Answer:

Solution:

For the two bulbs in series, equivalent power is

$P^{'} = \frac{P_{1} P_{2}}{P_{1} + P_{2}} = \frac{P P}{P + P}$

$P^{'} = \frac{(100) (100)}{100 + 100}$

$P^{'} = 50 W$

This $P^{'}$ is in parallel with other bulb. Therefore overall equivalent power is

$P_{e q} = P' + 100 W$

$P_{e q} = 150 W$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

⏱ 2mℹ️ Source: PYQ_2020

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