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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical PowerMedium2 minPYQ_2008

PhysicsMediumsingle choice

A bulb of $25 W, 200 V$ and another bulb of $100 W, 200 V$ are connected in series with a supply line of $220 V$ . Then

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Solution:

Resistance of $25 W, 200 V$ bulb $R_{1} = \frac{( 200 ) ^{2}}{25} Ω$ Resistance of $100 W, 200 V$ bulb $R_{2} = \frac{( 200 ) ^{2}}{100} Ω$ . Clearly, $R_{1} > R_{2} . ∴ H_{1} > H_{2}$ . $∴ 25 W$ bulb will glow more brightly.

Stream:AIIMSSubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

⏱ 2mℹ️ Source: PYQ_2008

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