Physics - Current Electricity Question with Solution | TestHub

As, the given case is of Wheatstone bridge, so equivalent resistance is given by

$R_{eq}=\frac{(R_1+R_2)(R_4+R_3)}{\left(R_1+R_2\right)+(R_4+R_3)}$



The equivalent resistance between point$\text{A}$and$\text{C}$

$R_{eq}=\frac{(4+6)(8+12)}{\left(4+6\right)+(8+12)}$

$=\frac{10\times 20}{10+20}=\frac{10\times 20}{30}=\frac{20}{3}\mathrm{ \Omega }$