Physics - Current Electricity Question with Solution | TestHub

The given circuit is a balanced Wheatstone bridge circuit. So, the resistance $7\Omega$ may be regulated. Therefore, we have the equivalent circuit as,
$\therefore$ The quivalent resistance between $A$ and $B$ is $R=\frac{4\times 8}{4+8}=\frac{32}{12}=\frac{8}{3}\Omega$