A capacitor of capacitance 100 μF is charged by connecting it to a battery of EMF 12 V and internal resistance 2 Ω . The time taken before 99 % of the maximum charge is stored on the capacitor-

Question

TestHub · Accepted Answer

During charging of capacitor, charge at any instant is

$q = q_{0} (1 - e^{t / R C})$

$0.99 q_{0} = q_{0} (1 - e^{- t / R C})$

$0.99 = (1 - e^{- t / R C})$

$0.01 = e^{- t / R C}$

$e^{t / R C} = 100$

$t = R C \ln (100)$

$t (2) (100 \times 10^{- 6}) (2 \times 2.303)$

$t = 0.92 m s$

Physics - Current Electricity Question with Solution | TestHub

Options:

Doubts & Discussion