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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityCircuit AnalysisEasy2 minPYQ_2020

PhysicsEasysingle choice

Two batteries, one of E.M.F. $18 V$ and internal resistance $2 Ω$ and other of E.M.F. $12 V$ and internal resistance $1 Ω$ , are connected as shown. The voltmeter $V$ will record a reading of

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Answer:

Solution:

Since the cells are in parallel, $V = \frac{\frac{E_{1}}{r_{1}} + \frac{E_{2}}{r_{2}}}{\frac{1}{r_{1}} + \frac{1}{r_{2}}} = \frac{\frac{18}{2} + \frac{12}{1}}{\frac{1}{2} + \frac{1}{1}} = \frac{21}{1.5} = 14 V$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Circuit Analysis

⏱ 2mℹ️ Source: PYQ_2020

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