Start Free Mock LoginAlready registered? Login here

Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical PowerMedium2 minQB

PhysicsMediumsingle choice

The figure shows three circuits $I, II$ and $III$ which are connected to a $3 V$ battery. If the powers dissipated by the configurations $I, II$ and $III$ are $P_{1}, P_{2}$ and $P_{3}$ respectively, then -

Options:

Answer:

Solution:

$P = \frac{V ^{2}}{R}$
$P \propto \frac{1}{R}$
$R_{e q}$ for $(I)$ circuit by balanced Wheatstone bridge
$R_{1} = 1Ω$

$R_{e q}$ for circuit $(II)$ by parallel combination
$\frac{1}{R _{2}} = \frac{1}{2} + \frac{1}{2} + \frac{1}{1}$

$R_{2} = \frac{1}{2}$

$R_{e q}$ for circuit $(III)$ by parallel and series combination
$R_{3} = 1 + \frac{1}{\frac{1}{2} + \frac{1}{2}}$
$R_{3} = 2$

so, $P_{2} > P_{1} > P_{3}$ .

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...