Physics - Current Electricity Question with Solution | TestHub

As shown in figure a shunt resistance $\left(S\right)$ is connected parallel to the galvanometer to convert it into an ammeter. Let $G$ is the resistance of the galvanometer.

Where $G=100\Omega$ and full-scale deflection current is $I_g=10m\text{A}=10\times 10^{-3}\text{A}$

For galvanometer $V_g=I_{g}G=10\times 10^{-3}\times 10=0.1volt$From the figure, the shunt is parallel to galvanometer

$\therefore$ $V_S=V_g\Rightarrow I_S\text{S}=V_g...\left(1\right)$For ammeter full-scale deflection current is

$I_S\left(=I-I_g\right)\approx 10\text{A}$

$\therefore$ from equation $\left(1\right)$

$10\text{S}=0\cdot 1\Rightarrow \text{S}=0\cdot 01\Omega$