Physics - Current Electricity Question with Solution | TestHub

A potentiometer is used to measure the potential difference between $\mathrm{A}$ and $\mathrm{B}$, the null point is obtained at $0.9\mathrm{m}$. Now potential difference between $\mathrm{A}$ and $\mathrm{C}$ is measured, the null point is obtained at $0\cdot 3\mathrm{m}$. The ratio $\frac{{\mathrm{E}}_2}{{\mathrm{E}}_1}$ is $\left({\mathrm{E}}_1>{\mathrm{E}}_2\right)$