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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityMicroscopicMedium2 minPYQ_2019

PhysicsMediumsingle choice

The current density in a solid cylindrical wire of radius $R$ , as a function of radial distance $r$ is given by $J (r) = J_{0} (1 - \frac{r}{R})$ . The total current in the radial region $r = 0$ to $r = \frac{R}{4}$ will be

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Answer:

Solution:

$i : d i = Jd A = J_{0} (1 - \frac{r}{R}) 2 π r d r = \int_{r = 0}^{r = \frac{R}{4}} J_{0} (1 - \frac{r}{R}) 2 π r d r = \frac{J _{0} 5 π R ^{2}}{96}$

Stream:AIIMSSubject:PhysicsTopic:Current ElectricitySubtopic:Microscopic

⏱ 2mℹ️ Source: PYQ_2019

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