Physics - Current Electricity Question with Solution | TestHub

Let$R_{eq}$be the equivalent resistance of this network.
$\Rightarrow R_{\text{eq}}=1+\frac{R_{\text{eq}}\times 1}{1+R_{\text{eq}}}$
$\Rightarrow R+R^2=1+R+R$
$\Rightarrow R^2-R-1=0$
$\Rightarrow R=\frac{1\pm \sqrt{1+4\times 1}}{2\times 1}$
$\Rightarrow R\text{ = }\frac{1\pm \sqrt{5}}{2}$
$\Rightarrow R\text{ =1.62 }\mathrm{\Omega }$