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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical PowerEasy2 minPYQ_2020

PhysicsEasysingle choice

An electric bulb rated for $500 W$ at $100 V$ is used in a circuit having a $200 V$ supply. The resistance $R$ that must be put in series with the bulb, so that the bulb is drawn $500 W$ is

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Answer:

Solution:

$P = V I, I = \frac{P}{V}$

or $I = \frac{500 W}{100 V} = 5 A$

Now, $5 R = 100$

or $R = 20 Ω$ .

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

⏱ 2mℹ️ Source: PYQ_2020

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