Physics - Current Electricity Question with Solution | TestHub

The equivalent circuit of the given circuit is as shown



Resistances 6$\mathrm{\Omega }$and 2$\mathrm{\Omega }$are in parallel

$\therefore R^{\prime }=\frac{6\times 2}{6+2}=\frac{3}{\mathrm{2 }}\mathrm{\Omega }$

Resistances$\frac{3}{\mathrm{2 }}\mathrm{\Omega }\mathrm{ }\mathrm{a}\mathrm{n}\mathrm{d}\mathrm{ }\mathrm{1.5 }\mathrm{\Omega }\mathrm{ }\mathrm{a}\mathrm{r}\mathrm{e}\mathrm{ }\mathrm{i}\mathrm{n}\mathrm{ }\mathrm{s}\mathrm{e}\mathrm{r}\mathrm{i}\mathrm{e}\mathrm{s}$

$\therefore R^{\prime \prime }=\frac{3}{2}+1.5=\mathrm{3 }\mathrm{\Omega }\mathrm{ }$

Resistances 3$\mathrm{\Omega }$and 3$\mathrm{\Omega }$are in parallel

$\therefore R=\frac{3\times 3}{3+3}=\frac{3}{2}$

The current,$I=\frac{V}{R}$

$=\frac{9}{3/2}=6\text{A}$