A meter bridge is set-up as shown, to determine an unknown resistance $X$ using a standard $10 ohm$ resistor. The galvanometer shows null point when tapping-key is at $52 cm$ mark. The end-corrections are $1 cm$ and $2 cm$ respectively for the ends $A$ and $B$ . The determined value of $X$ is

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Applying the condition of balanced Wheatstone bridge, we get ​ 10Ω X ​ = ( 48 + 2 ) cm ( 52 + 1 ) cm ​ = 50 53 ​ , X = 10Ω × 50 53 ​ = 10.6Ω ​

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