The masses of three copper wires are in the ratio 2 : 3 : 5 and their lengths are in the ratio 5 : 3 : 2 . Then, the ratio of their electrical resistances is

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using, R = ρ A 1 ​ R 1 ​ : R 2 ​ : R 3 ​ = A 1 ​ 1 1 ​ ​ : A 2 ​ 1 2 ​ ​ : A 3 ​ 1 3 ​ ​ = V 1 ​ 1 1 2 ​ ​ : V 2 ​ 1 2 2 ​ ​ : V 3 ​ 1 3 2 ​ ​ = ( m 1 ​ d ) 1 1 2 ​ ​ : ( m 2 ​ d ) 1 2 2 ​ ​ : ( m 3 ​ d ) 1 3 2 ​ ​ = m 1 ​ 1 1 2 ​ ​ : m 2 ​ 1 2 2 ​ ​ : m 3 ​ 1 3 2 ​ ​ = 2 5 2 ​ : 3 3 2 ​ : 5 2 2 ​ = 125 : 30 : 8 ​

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