Physics - Current Electricity Question with Solution | TestHub

$\mathrm{R}=\mathrm{\rho }\frac{\mathrm{l}}{\mathrm{A}}$

Since we know resistivity is given by $\mathrm{\rho }=\frac{\mathrm{m}}{{\mathrm{ne}}^2\mathrm{r}}$

Resistance $\mathrm{R}=\frac{\mathrm{ml}}{{\mathrm{ne}}^2\mathrm{\tau A}}$

where,
$\mathrm{m}=$ Mass of electron
$\mathrm{l}=$ length of conductor
$\mathrm{n}=$ charge density
$\text{e}=$ charge of electron
$\mathrm{\tau }=$ relaxation time
$\mathrm{A}=$ cross-sectional area