Physics - Current Electricity Question with Solution | TestHub

The resistance of any bulb$=V^2/P$

Current through ammeter at shown position$=3i_1$

current in any $1$ bulb$=i_1=\frac{V}{R}=\frac{V}{V^2/P}$$=\frac{P}{V}=\frac{100}{220}$

Through ammeter, $\Rightarrow i_{\mathrm{net}}=3i_1=\frac{300}{220}$$=1.35 \mathrm{A}$