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PhysicsCurrent ElectricityCircuit AnalysisMedium2 minQB

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A current of $15 mA$ flows in the circuit as shown in figure. The value of potential difference between the points $A$ and $B$ will be

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Answer:

Solution:

Using current division rule,
Current, $i_{1} = \frac{5}{10 + 5} \times 15 mA = 5 mA$
Now, using Kirchhoff's voltage law- in lower loop,
$V_{A} - 5 i - 10 i_{1} - 10 i = V_{B}$
Potential difference between $A$ and $B$ is $V_{A} - V_{B} = 75 + 50 + 150 = 275 V$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Circuit Analysis

⏱ 2mℹ️ Source: QB

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