Physics - Current Electricity Question with Solution | TestHub

It is a balanced Wheatstone bridge. Hence no current flows through resistance of arm BDand the resistance of arm BD is ineffective
$\therefore \frac{R_{AB}}{R_{BC}}=\frac{R_{AD}}{R_{DC}}$ $\Rightarrow \frac{\stackrel{◯}{R}\Omega }{\stackrel{◯}{R}\Omega }=\frac{\stackrel{◯}{R}\Omega }{\mathrm{๑}\Omega }$ Resistance of arm $ABC=5\Omega +5\Omega =10\Omega$ Resistance of arm $ADC=5\Omega +5\Omega =10\Omega$ The effective resistance between $A$ and $C$ is $\frac{1}{R_{AC}}=\frac{1}{10}+\frac{1}{10}$ or $R_{AC}=5\Omega$ Now the equivalent circuit becomes $\therefore$ The equivalent resistance of the circuit
$\frac{1}{R}=\frac{1}{5}+\frac{1}{5}$ or $R=2.5\Omega$ Current in the circuit, $I=\frac{V}{R}=\frac{25}{2.5}=10\mathrm{A}$