Physics - Current Electricity Question with Solution | TestHub

$V_{AB}=$ Equivalent emf of two batteries in parallel. $$\begin{array}{rl}& =\frac{E_1/r_1+E_1/r_2}{1/r_1+1/r_2}\\ & =\frac{(6/1)+(3/2)}{(1/1)+(1/2)}=5\mathrm{V}\end{array}$$ $\therefore$ Answer is 5 . Analysis of Question (i) In my opinion this is the simplest question of JEE 2011. (ii) When no current is drawn from this equivalent battery, then $$V_{AB}=V=E$$ Otherwise, $V=E\pm$ ir (iii) Similar type of question was asked in JEE 1981 and cancelled paper of JEE 1997.