A circuit contains an ammeter, a battery of 30 v and a resistance 40.8 ohm all connected in series. If the ammeter has coil of resistance 480 ohm and a shunt of 20 ohm, the reading in the ammeter will

Question

A circuit contains an ammeter, a battery of 30 v and a resistance 40.8 ohm all connected in series. If the ammeter has coil of resistance 480 ohm and a shunt of 20 ohm, the reading in the ammeter will be:NEET 2015 (Phase 2)

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Answer:

D

Solution:

Resistance of ammeter $= \frac{480 \times 20}{480 + 20} = 19.2 Ω$

$i = \frac{30}{40.8 + 19.2} = 0.5 A$

TestHub · Accepted Answer

Resistance of ammeter = 480 × 20 480 + 20 = 19.2 Ω i = 30 40.8 + 19.2 = 0.5 A

Physics - Current Electricity Question with Solution | TestHub

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