Physics - Current Electricity Question with Solution | TestHub

Mass $=\left(\pi {\mathrm{r}}_1^2{\ell }_1\right)\sigma$ (Ist wire) $\begin{array}{rl}& \text{ Mass }=\left(\pi {\mathrm{r}}_1^2{\ell }_2\right)\sigma (2\text{ nd wire) }\\ & \left(\pi {\mathrm{r}}_1^2{\ell }_1\right)\sigma =\left(\pi {\mathrm{r}}_2^2{\ell }_2\right)\sigma \end{array}$ $\begin{array}{rl}& \left(\pi {\mathrm{r}}_1^2{\ell }_1\right)\sigma =\left(\pi {\mathrm{r}}_2^2{\ell }_2\right)\sigma \\ & \frac{{\ell }_1}{{\ell }_2}={\left(\frac{r_2}{r_1}\right)}^2\end{array}$ $\frac{R_1}{R_2}=\frac{\rho \frac{{\ell }_1}{A_1}}{\rho \frac{{\ell }_2}{A_2}}=\frac{{\ell }_1}{{\ell }_2}\times \frac{A_2}{A_1}=\frac{{\ell }_1}{{\ell }_2}\times {\left(\frac{r_2}{r_1}\right)}^2$ $\begin{array}{rl}& ={\left(\frac{r_2}{r_1}\right)}^4\\ & \Rightarrow 16:1\end{array}$