Physics - Current Electricity Question with Solution | TestHub

Equivalent resistance between A and B = series combination of$\mathrm{1 }\text{Ω}$and$\mathrm{2 }\text{Ω}$in parallel with$\mathrm{3 }\text{Ω}$resistor.



$\frac{1}{R}=\frac{1}{3}+\frac{1}{3}=\frac{2}{3}$or$R=\mathrm{1.5 }\text{Ω}$.

$\therefore$Current in the circuits ,$I = \frac{V}{R}= \frac{1.5 }{1.5}= 1 \mathrm{A}$

Since the resistance in arm ACB = resistance in arm$AB=\mathrm{3 }\text{Ω}$, the current divided equally in the two arms. Hence the current through the$\mathrm{3 }\text{Ω}$resistor =$\frac{I}{2}=0.5 \mathrm{A}$.