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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityBatteryMedium2 minPYQ_2009

PhysicsMediumsingle choice

Two identical cells each of emf $E$ and internal resistance $r$ are connected in parallel with an external resistance $R$ . To get maximum power developed across $R$ , the value of $R$ is

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Answer:

Solution:

$R_{e q} = \frac{r}{2}$ $I = \frac{2 E}{r + 2 R}$ For max. power consumption. I should be max. So denominator should be min. for that $r + 2 R = (r,)$

Stream:WBJEESubject:PhysicsTopic:Current ElectricitySubtopic:Battery

⏱ 2mℹ️ Source: PYQ_2009

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