A 5 V battery with internal resistance 2Ω and a 2 V battery with internal resistance 1Ω are connected to a 10Ω resistor as shown in the figure. The current in the 10Ω resistor is

Question

TestHub · Accepted Answer

​ V P 2 ​ ​ − V P 1 ​ ​ = 2 1 ​ + 10 1 ​ + 1 1 ​ 2 5 ​ + 10 0 ​ − 1 2 ​ ​ I = 10 V P 2 ​ ​ − V P 1 ​ ​ ​ = 0.03 from P 2 ​ → P 1 ​ ​

Physics - Current Electricity Question with Solution | TestHub

Options:

Doubts & Discussion