Physics - Current Electricity Question with Solution | TestHub

Key Idea : In parallel resistances, potential difference across them is same. Potential difference across PM $V=4\times 1=4\text{ volt (ie, across }4\Omega )$ Equivalent resistance of lower side arm, $R_{eq}=1+\frac{0.5\times 0.5}{0.5+0.5}=1.25\Omega$ Now the circuit can be shown asLet current I flows in lower branch, so $\begin{array}{rl}1.25I& =4\mathrm{V}\\ I& =\frac{4}{1.25}=3.2\mathrm{A}\end{array}$ Therefore, 3.2 A current flows in $1\Omega$ resistance, hence potential difference between $M$ and $N$ is $V^{\prime }=3.2\times 1=3.2$ volt