In a tangent galvanometer, a current of 1 A produces a deflection of 3 0 ∘ . The current required to produce a deflection of 6 0 ∘ is

Current in tangent galvanometer I = G H tan θ Where G = galvanometer constant H = earth’s horizontal field = constant ∴ I 2 I 1 = t a n θ 2 t a n θ 1 ⇒ I 2 1 = t a n 6 0 ∘ t a n 3 0 ∘ ⇒ I 2 = t a n 3 0 ∘ t a n 6 0 ∘ = 0.5774 1.7321 = 2.999 A ˚ ⇒ I 2 ≃ 3 A

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PhysicsCurrent ElectricityEquivalent ResistanceHard2 minPYQ_2006

PhysicsHardsingle choice

In a tangent galvanometer, a current of $1 A$ produces a deflection of $3 0^{\circ}$ . The current required to produce a deflection of $6 0^{\circ}$ is

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Current in tangent galvanometer $I = \frac{H}{G} tan θ$ Where $G =$ galvanometer constant $H = earth’s horizontal field = constant$ $∴ \frac{I _{1}}{I _{2}} = \frac{t a n θ _{1}}{t a n θ _{2}} \Rightarrow \frac{1}{I _{2}} = \frac{t a n 3 0 ^{\circ}}{t a n 6 0 ^{\circ}}$ $\Rightarrow I_{2} = \frac{t a n 6 0 ^{\circ}}{t a n 3 0 ^{\circ}} = \frac{1.7321}{0.5774} = 2.999 \overset{˚}{A} \Rightarrow I_{2} ≃ 3 A$

Stream:VITEEESubject:PhysicsTopic:Current ElectricitySubtopic:Equivalent Resistance

⏱ 2mℹ️ Source: PYQ_2006

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