Physics - Current Electricity Question with Solution | TestHub

Applying Kirchhoff's voltage law,

$I\left(2+8\right)=6+4$

$I.10=10$

$I=\mathrm{1 }\mathrm{A}$

$V_{\mathrm{A}}-\left(I\times 2\right)+6=V_B$

$V_A-V_B=\left(1\times 2\right)-6$

And$V_{BA}=\mathrm{4 }\mathrm{V}$