Start Free Mock LoginAlready registered? Login here

Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical PowerHard2 minPYQ_2005

PhysicsHardsingle choice

$For ensuring dissipation of same energy in all$ $th r$ e $e$ resistors $(R_{1}, R_{2}, R_{3})$ connected as shown in figure, their values must be related as

Options:

Answer:

Solution:

As the voltage in $R_{2}$ and $R_{3}$ is same therefore, according to, $H = \frac{V ^{2}}{R} \cdot t, R_{2} = R_{3}$ Also the energy in all resistance is same. $∴ i^{2} R_{1} t = i_{1}^{2} R_{2} t$
$U sing \dot{h}_{1} = \frac{R _{3}}{R _{2} + R _{3}} i = \frac{R _{3}}{R _{3} + R _{3}} i = \frac{1}{2} i$ Thus $i^{2} R_{1} t = \frac{i ^{2}}{4} R_{2} t$ or, $R_{1} = \frac{R _{2}}{4}$ .

Stream:AIIMSSubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

⏱ 2mℹ️ Source: PYQ_2005

Doubts & Discussion

Loading discussions...