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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical instrumentMedium2 minPYQ_2004

PhysicsMediumsingle choice

A galvanometer of $50 ohm$ resistance has 25 divisions. A current $4 \times 1 0^{- 4}$ ampere gives a deflection of one division. To convert this galvanometer into a voltmeter having a range of 25 volts, it should be connected with a resistance of:NEET 2004

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Solution:

Total current in the galvanometer $=$ $25 \times 4 \times 1 0^{- 4} A I_{g} = 1 0^{- 2} A$ The value of resistance connected in series to convert galvanometer into voltmeter of $25 V$ is $R = \frac{V}{I _{g}} - G = \frac{25}{1 0 ^{- 2}} - 50 = 2450Ω$

Stream:NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Electrical instrument

⏱ 2mℹ️ Source: PYQ_2004

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