In the circuit shown in the figure, reading of voltmeter is $V_{1}$ when only $S_{1}$ is closed, reading of voltmeter is $V_{2}$ when only $S_{2}$ is closed and reading of voltmeter is $V_{3}$ when both $S_{1}$ and $S_{2}$ are closed. Then -

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When only S 1 is closed, i = E R + 3 R = 3 4 R Reading V 1 = 3 R = 3 E 4 = 0.75 E When only S 2 is closed i = E 7 R Reading V 2 = i 6 R = 6 E 7 = 0.86 E When S 1 and S 2 both are closed, R e q = R + 2 R = 3 R i = E 3 R , V 3 = i 2 R = 2 E 3 = 0.67 E , V 2 > V 1 > V 3

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