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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle describes a horizontal circle in a conical funnel whose inner surface is smooth with the speed of $0.5 m s^{- 1}$ . What is the height of the plane of the circle from the vertex of the funnel?

Options:

Answer:

Solution:

$N \sin θ = m g$

$N \cos θ = m v^{2} / r$

Dividing above equations

$\Rightarrow \tan θ = r g / v^{2}$

$\Rightarrow \frac{r}{h} = \frac{r g}{v^{2}}$

$\Rightarrow h = \frac{v^{2}}{g} = 2.5 c m$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Circular MotionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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