Physics - Circular Motion Question with Solution | TestHub

(P) $T=mg\cos 53^{\circ }$ ,$T=\frac{3mg}{5}$ ⟹ P → (3).

(Q) $T\cos 37^{\circ }=mg$ ,$T=\frac{5mg}{4}$ ⟹ Q → (2).

(R) $T\cos 53^{\circ }=mg$ ,$T=\frac{5mg}{3}$ ⟹ R → (4).

(S) $a=g\sin 37^{\circ }$$T=mg\cos 37^{\circ }$ ,$T=\frac{4mg}{5}$ ⟹S → (1).