Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionDynamicsHard2 minQB

PhysicsHardsingle choice

Passage / Comprehension

When an object is seen from rotating frame of referance, coriollis force acts on the object which is equal to $2 m (V \times ω)$ where $V$ is velocity of object with respect to rotating frame and $ω$ is angular velocity of rotating frame.

By what displacement stone is pushed due to coriolis force when it hits ground in previous problem.

Options:

Answer:

Solution:

$F = 2 mω v cos θ = 2 mω cos θ \cdot g t = ma$ ⇒ $a = 2 ω g cos θ \cdot t$ .

$v = \int_{0}^{t} a d t = ω g cos θ t^{2}$ ; displacement $= \int_{0}^{t} v d t = \frac{ω g c o s θ t ^{3}}{3}$ .

With $t = \frac{2 h}{g}$ and $θ = 6 0^{\circ}$ ( $cos θ = \frac{1}{2}$ ): $x = \frac{ω g}{6} (\frac{2 h}{g})^{3/2}$ - (B)

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Dynamics

⏱ 2mℹ️ Source: QB

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