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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A particle moves along a circle of radius $r$ with constant tangential acceleration. If the velocity of the particle is $v$ at the end of second revolution after the revolution has started then the tangential acceleration is

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Answer:

Solution:

Using $v^{2} - u^{2} = 2 a s$ and $u = u_{1}$ and $s = 4 π r$

$∴ 2 a s = v^{2} \Rightarrow \frac{v^{2}}{2 s} = a = \frac{v^{2}}{2 \times 4 π r} = \frac{v^{2}}{8 π r}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Circular MotionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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