Two bodies A and B are moving with same constant speed v in clockwise direction in a horizontal circle of radius R and are initially dimetrically opposite. The particle B now achieves a tangential acceleration $am / s^{2}$ . Then :

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TestHub · Accepted Answer

Relative distance to close along the circle is half a circumference:
$s_{rel} = π R$
B gains relative tangential speed at rate a:
$s_{rel} = \frac{1}{2} a t^{2}$
Set the two distances equal:
$\frac{1}{2} a t^{2} = π R$
$t = \frac{2 π R}{a}$
Relative speed just before collision:
$v_{rel} = a t = 2 πa R$
Hence B and D.

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