Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionKinematicsEasy2 minQB

PhysicsEasymultiple choice

A particle is performing circular motion of radius 1 m . Its speed is $v = (2 t^{2}) m / s$ . Then at $t = 1 s$ :

Answer:

A, B

Solution:

$a_{t} = \frac{d v}{d t} = 4 t = 4.1 = 4$

$a_{c} = \frac{v ^{2}}{r} = \frac{2 ^{2}}{1} = 4$

$a = a_{t}^{2} + a_{c}^{2} = 4^{2} + 4^{2} = 42$

Ans : A, B

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Kinematics

⏱ 2mℹ️ Source: QB

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