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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionDynamicsMedium2 minQB

PhysicsMediumsingle choice

A turn has a radius of 10 m. If the road is horizontal (no banking), what should be the minimum friction coefficient so that a scooter going round it at $18 km / h$ does not skid? (Take $g = 10 m / s^{2}$ .)

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Answer:

Solution:

On a horizontal road friction provides the centripetal force, with $v = 18 km / h$
$= 5 m / s$ :
$μ m g so μ = \frac{m v ^{2}}{R}, = \frac{v ^{2}}{R g} = \frac{25}{100} = 0.25.$

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Dynamics

⏱ 2mℹ️ Source: QB

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