Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionKinematicsMedium2 minQB

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A uniform chain has a mass $M$ and length $L$ . It is placed on a frictionless table with length $ℓ_{0}$ hanging over the edge. The chain begins to slide down. The speed $V$ with which the chain slides away from the edge is given by

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Answer:

Solution:

$λ = \frac{M}{L}$ .

$y_{i} = \frac{λ ℓ _{0} \cdot \frac{ℓ _{0}}{2}}{M} = \frac{ℓ _{0}^{2}}{2 L}$

$y_{f} = \frac{L}{2}$

$Δ y = y_{f} - y_{i} = \frac{L}{2} - \frac{ℓ _{0}^{2}}{2 L}$

$\frac{1}{2} M v^{2} = M g Δ y$

$v^{2} = 2 g (\frac{L}{2} - \frac{ℓ _{0}^{2}}{2 L})$

$v = g (L - \frac{ℓ _{0}^{2}}{L})$

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:Kinematics

⏱ 2mℹ️ Source: QB

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