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Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular Motion248Medium2 minQB

PhysicsMediumsingle choice

A particle moves along a circle of a fixed radius with a variable centripetal acceleration $a_{n} = kt^{n}$ , where k is a constant and t time. If slope of P-t graph on $lo g - lo g$ scale is 2 then value of n is :- (here P is instantaneous power)

Options:

Answer:

Solution:

$\frac{v ^{2}}{r} = k t^{n}$ , so $v = k r t^{n /2}$

$P = m \frac{d v}{d t} v = \frac{mk r n}{2} t^{n - 1}$

Slope of log P vs log t = n - 1 = 2, so n = 3

Answer (D)

Stream:JEESubject:PhysicsTopic:Circular MotionSubtopic:248

⏱ 2mℹ️ Source: QB

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