Start Free Mock LoginAlready registered? Login here

Physics - Circular Motion Question with Solution | TestHub

PhysicsCircular MotionMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

Two particles of masses $m$ and $2 m$ are connected by a string of length $L$ and placed at rest over a smooth horizontal surface. The particles are then given velocities as indicated in the figure shown. The tension developed in the string will be

Options:

Answer:

Solution:

$V_{c} = \frac{2 m v - m v}{(2 m + m)} = \frac{v}{3}$

$V_{r e l} = v - \frac{v}{3} = (\frac{2 v}{3})$

$r_{1} = \frac{m L}{3 m} = \frac{L}{3}$

$∴ T = \frac{(2 m) \times {(\frac{2 v}{3})}^{2}}{(\frac{L}{3})} = \frac{8 m v^{2}}{3 L}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Circular MotionSubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...