A small block of mass 100 g is tied to a spring of spring constant 7 . 5 N m - 1 and length 20 cm . The other end of spring is fixed at a particular point A . If the block moves in a circular path on

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A small block of mass 100 g is tied to a spring of spring constant 7 . 5 N m - 1 and length 20 cm . The other end of spring is fixed at a particular point A . If the block moves in a circular path on a smooth horizontal surface with constant angular velocity 5 rad s - 1 about point A , then tension in the spring is

TestHub · Accepted Answer

Centripetal force will be provided by the spring force. Let the elongation in the spring be $x$ , then we can write
$\Rightarrow k x = m ω^{2} (r + x)$
$\Rightarrow 7.5 x = 2.5 (0.2 + x)$
$\Rightarrow x = \frac{0.5}{5} = 0.1$
Therefore, required tension will be $T = k x = 0.75 N$ .

Physics - Circular Motion Question with Solution | TestHub

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